
复制isdigit:=FALSE; m := length(password); FOR i IN 1..10 LOOP FOR j IN 1..m LOOP IF substr(password,密码
j,1) = substr(digitarray,i,1) THEN isdigit:=TRUE; GOTO findchar; END IF; END LOOP; END LOOP; IF isdigit = FALSE THEN raise_application_error(-20003, Password should contain at least one digit, one character and one punctuation); END IF; 1.2.3.4.5.6.7.8.9.10.11.12.13.
作者:人工智能